Number theory·OpenAI Math·Result 029
Primitive roots for every admissible integer base
One of the 372 results in OpenAI's public mathematics catalogue, filed under number theory: 2 preprints, the latest dated 4 October 2026. This page quotes OpenAI's own summary of the claim, links the papers and abstracts, and will embed the animation.
Latest paper
Primitive roots for every admissible integer base
The animation for this result has not been released yet. Subscribe on YouTube to catch it.
What OpenAI claims
Proves the infinitude assertion in Artin's primitive root conjecture for every integer a that is neither −1 nor a square. For each such base, at least ca x/(log x)2 primes in every sufficiently large interval (x,2x) have primitive root a, with ca > 0.
Papers (2)
Primitive roots for every admissible integer base
We prove the infinitude assertion in Artin's primitive root conjecture: for every integer a that is neither −1 nor a square, there are at least ca x/(log x)2 primes in (x,2x) with primitive root a, for some ca > 0 and every sufficiently large x.
Simultaneous primitive roots: a conditional lower bound for prime bases
For every fixed finite set of distinct positive primes, we prove that at least cx/(log x)2 primes in (x,2x) have every member of the set as a primitive root, for some c > 0 and all sufficiently large x. The result assumes four explicitly stated analytic and sieve inputs from the companion paper on primitive roots for admissible integer bases.
Status
Preprint. The papers have not been independently reviewed. Treat the result as OpenAI's claim until other mathematicians have checked it. If a video exists, it illustrates the statement; it is not the proof.
Related results in Number theory
- 030Modularity of elliptic curves over imaginary quadratic fields
- 031Uchida’s conjecture for open homomorphisms of Galois groups
- 001Milne’s rationality conjecture and algebraic specializationVideo
- 002The full BSD formula from low Selmer corankVideo
- 003The quasi-Riemann hypothesisVideoLean
- 004Hilbert’s tenth problem over ℚVideo